Questions & Answers for: exp 84

EXP 1981-83 1.6L LN7, Lynx 1984-85 2.0L Escort, Tempo 1993-95 2.0L Probe 1986-88 2.0L Ranger 1984-87 2.0L Lynx, Topaz Diesel 1985 2.2L Ranger 1989-92 2.2L Probe 1986-88 2.3L Ranger 1986-87 2.3L Diesel

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Question about TI-84 Plus Calculator

1 Answer

...exp reg line from data about dice decay and I'm getting an error message that says domain error. BTW using the TI-84 plus I had this problem too, turns out that if any of your y-coordinates are 0 or ...

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...TI 84 silver plus from the exp button down only divides and doesn't perform the proper funtion. What is wrong with it? Batteries or solar cell dead on these TI's Come cheap nowadays, get a Casio

Question about FX-9750GPlus Calculator

1 Answer

...84 leaving me left behind trying to find ways to do the same exact thing. how do i find the equation of a best fitting line? Hello, I am sorry but I will have to assume that you know how to enter the ...

Question about TI-84 Plus Calculator

1 Answer

where's the EXP button on TI-30XB? i need to answer a problem just like this : -log2.5(EXP)^-4 To raise e to the xth power, use e^x, which is the second function of the LN key to the left of the 4 key

Question about TI-84 Plus Calculator

1 Answer

I want to find the exp of a negative number on my TI84plus. When I do e^(-4) I get a a syntax error. Why can't I do this operation? Use the (-) key just to the right of the decimal point to enter ...

Question about TI-84 Plus Silver Edition Graphic Calculator

1 Answer

...and it does not help. ANy suggestions?? At first in Y editor type Y1=2*cosx and for example y2=[5*exp(-x)]-5 and then graphing it. Set RAD mode of course. See captured ...

...value in rectangular form a + bi. The complex value can have any complex form. However, an r*exp(i*theta) causes an eror in Degree angle mode  according to the TI avowal. See

Question about TI-84 Plus Calculator

1 Answer

...3(e^(1/z-1)) which type of complex singularity is this ?? See Laurent series of this function: z^(3)exp^((1/z-1))=z^(3)+z^(2)(1-z)+(z(1-z)^(2))/2!+1-(1-z)^(3)/3!+... You can see it has an essential ...

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