Questions & Answers for: equation circle radius center

...circle equation? and if (-2,2) is the center of the circle the equation should look like this: (x+2)^2+(Y-2)^2=R^2 And now only R is needed. given 2x-5y+4=0 equation of line perpendicular we can ...

...will be prompted to enter the values for H,K, and R You can also use the general equation for a circle aX^2 +aY^2+BX+CY +D=0 Enter the values of a, B, C and D.Change the values to get what you

equation. if you draw a circle on a piece of paper then draw a triangle around it where is the center? if the triangle were a perfect equilateral then the circle would be a perfect circle touching the

find the equation of the locus of a variable point P if P is 2 units distant from (-1,-2) The equation of a circle with radius 2 and centered on (-1, -2) is (x+1)^2 + (y+2)^2 -4 = 0

...at the origin (0,0) and radius 4. By the way the equation of a circle is not a function. You have to cut it into the upper brach and the lower part to graph it. y=+SQRT(16-x^2) and

...equation of the circle into the form (x-h)^2+(y-k)^2=R^2. Here (h,k) would be the center and R the radius.To do that complete the two squares.x^2-2x=x^2-2x+1-1=(x^2-2x+1)-1=(x-1)^2 -1.Do the same for ...

circle equation how do you measure diameter If you know the center, measure the distance between the center and one point on the circumference. Measure with the opening of a compass and report on a ...

...your answer. x^2 + y^2 = 5 The equation of a circle is (x-h)^2+(y-k)^2=r^2. Since h and k are 0, we have x^2 + y^2=r^2. Since r= 5, r^2=25. Thus, the equation is x^2 + y^2 = 25. Good luck. ...

...equation in standard form for the circle with radius 1 centered at the origin. The formula for a circle in standard form in (x-h)^2 + (y-k)^2 = r^2, where r is the radius, the point (h,k) is the ...

...3) and whose radius measures4 is it A, B, C or D? A. The equation of a circle is (x-a)^2 + (y-b)^2 = r^2, with (a,b) being the centre of the circle and r being the radius.

Good ...