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Anonymous Posted on Feb 09, 2010

I DO NOT KNOW HOW TO FIND THE MINIMUM ON A GRAPH WHEN IT IS ON MY CALCULATOR

  • Anonymous Feb 09, 2010

    THIS WAY DOES NOT GIVE YOU THE EXACT ANSWER IT IS OFF

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k24674

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  • Texas Instru... Master 8,093 Answers
  • Posted on Feb 09, 2010
k24674
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After you have drawn your graph, press [2nd][TRACE] to access the (CALC) menu
I DO NOT KNOW HOW TO FIND THE MINIMUM ON A GRAPH - 945fb0b.jpg
In the above screen (on your calculator) press [3:minimum]
You will be promped for the lower bound of the domain where you think the minimum liesI DO NOT KNOW HOW TO FIND THE MINIMUM ON A GRAPH - 5d2b86d.jpg src="/uploads/images/5d2b86d.jpg" alt="5d2b86d.jpg" class="h_mi" />
Notice the dark spot on the curve near the X axis: That is what the calculator suggests as a lower bound. Since it is rather close to the minimum you are well advised to select this as a lower bound. To accept it press [ENTER].
You are then prompted for the right bound. Be ready to move the cursor to the right side of the minimum. That is what I had to do to get the folI DO NOT KNOW HOW TO FIND THE MINIMUM ON A GRAPH - 4263d02.jpgen. Notice the mark on the curve at X=4.7
4263d02.jpg
Press [ENTER] to accept or type in a reasonable value.
The calculator prompI DO NOT KNOW HOW TO FIND THE MINIMUM ON A GRAPH - a07ff44.jpga guess. Enter a value that lies in the interval [left bound, right bound] and presI DO NOT KNOW HOW TO FIND THE MINIMUM ON A GRAPH - 94af57a.jpgr />I

As you can see, I entered value X=3 and pressed [ENTER]
94af57a.jpg
Here is the result. Enjoy
148f529.jpg

If you have to look for a maximum, the procedure is the same, except that at the begining of the search you select [4:maximum] on the first screen capture (see above.)

  • 1 more comment 
  • k24674 Feb 09, 2010

    OOPS: The sentence
    "Notice the dark spot on the curve near the X axis"
    should read
    "Notice the dark spot on the curve near the Y axis"



  • k24674 Feb 10, 2010

    There is no such thing as an exact result with a calculator. Every thing is approximate. This is the way to do it. Read your calculator manual.

    I took the example of a function that has a minimum to show you how to do it. I figuratively took you by the hand. All you have to do is enter your function. I SHOWED you every single step, leaving nothing out. I even went out of my way, on my own time at no cost to you, to do the screen captures from my calculator, tansfer them to my computer and insert them in the post, in the hope that it will help you and any reasonably intelligent person who can read and imitate what is shown.
    If you are unable to benefit from these overly detailled explanations, then my friend, you are in serious trouble with your mathematics, and you should hire a tutor.

    I do not know whether I should tell you that, but if you want to obtain the exact result, here is how it is done (with pen and paper). If you take college calculus you will learn it.


        Calculate the first derivative of your function

        Find the points (x-values) where that first derivative vanishes (has value 0). That entails solving by hand a (generally) non-linear equation.

        Calculate the second derivative of your original function.

        At the points where the first derivative vanishes (at the x-values calculated in point 2) evaluate the second derivative: replace the x-values in the expression for the 2nd derivative.

        If the 2nd derivative is positive, then the original function has a minimum.

        If the 2nd derivative is negative, then the oroginal function has a maximum.
    Lets us see how you fare with this.
    If you do not understand ask for explanations.



  • k24674 Feb 10, 2010

    I forgot to tell you: On the web, if you use capital letters you are signifying that you are SHOUTING.

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Related Questions:

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Not found message when trying to get the minium on the graph

Either you have an idea where the extremum (minimum/ maximum) might be (its x-value and maybe its y-value) and you set the center of the graph accordingly, or you zoom out until you locate it.Them you change the center of the graph to be about the position of the extremum. There is no ready made recipe that will work for any function. Just Trial and error. It might help calculating a few values of the function for x=0, x=-10. If the extremum happens to be within the table that the calculator generated to draw the graph, then it will be found.

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Minimum point of a plot graph

Two, since only one straight line exists that goes through the same two points.

Alternatively, you could define a straight line with one point and a slope.
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After you create a graph, have the calculator draw it. To find the minimum or maximum press SHIFT F5 G-Solv. Use the appropriate tabs MAX, MIN.
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How do I find the max and min value of a sine curve

The maximum value of the sine function is positive one, the minimum value is negative one. Within any limited range the maximum and minimum will fall between the two extremes.
If you have a graphing calculator, the easiest way to to find the maximum and minimum values of a sine curve is to plot it. Some calculators will even automatically find the max and min values. Others you'll have to eyeball it.
If you don't have a graphing calculator, you can calculate the value at a series of points and hone in the max and min values.
If you need further assistance, please reply to this post and specify the make and model of your calculator.
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Minimum or maximum value of a parabola

Follow these steps: graph the parabola and after that 2nd then CALC keypad. To find extreme value of the function select 3: min or 4: max options. Select the function and set left bound, right bound(using left and right arrows) by pressing ENTER. You can see images bellow for all these steps for the y=-2x^2+5x+3

1. step: graphing parabola
3_9_2012_7_34_06_pm.jpg

2. step: left or lower bound
3_9_2012_7_36_01_pm.jpg

3. step: right or upper bound
3_9_2012_7_37_33_pm.jpg

4.step: extreme value of the function
3_9_2012_7_39_04_pm.jpg
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I need to find decreasing and increasing intervals and I dont know how to do this on my TI 83

While your TI-83 plus cannot explicitly find increasing or decreasing intervals, it can find the minimum(s) and maximum(s) of a function.
Press the "Y=" button.
Enter the equation in "y=" format into the first open equation.
Press the "GRAPH" key.
If the maximum and minimum of the curve are not shown in the window it has, press ZOOM->0.
Press 2ND->CALC (under the "TRACE" key).
Press 3 if you are trying to find a min, 4 if you're trying to find a max.
It will ask for bounds. Enter a left and right bound by looking at the graph itself and choosing a left bound that is clearly to the left of the min/max, and a right bound clearly to the right of the min/max.
Then it will ask you to guess a value. You can skip this step by pressing ENTER instead of entering a value.
It will calculate the value. To find increasing/decreasing intervals, just know that every interval with a minimum as the left bound and a maximum as the right bound is increasing, and vice versa.
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When I'm entering a quadratic function, I'm getting the graph of something that is not a parabola like it should be. However, when I graph x^2 by itself, it looks the way it should. What can I do to fix...

The actual graph depends on the constants (parameters) that are in the equation. Try playing with the dimensions of the window by zooming in or zooming out.
The most interesting part of the graph is the region near the maximum or minimum.
Here is a graph of the function y=X^2-5X 13 when drawn with standard window dimensions
3b585d8.jpg
Not very revealing. However if you press the Zoom key and select [2:ZoomIn] you see this (no changes) but the calculator is ready to accept your input concerning the new center of the graph.
bcd4c3e.jpg
At this stage, use the Arrow keys to move the center of the graph to another point as in the next screen capture.

0e09736.jpg
Notice the new center as a sign on the screen and its coordinates at the bottom. By pressing [ENTER] you get this
fc695b8.jpg
If you keep Zooming in you may end up having something that does not look like a parabola anymore.
4ea7132.jpg

To summarize: Use the Zoom In or Zoom Out functions or find where the minimum/maximum is, center the graph on that point and modify the windows dimensions (Xmin, Xmax, Ymin, and Ymax) so as to get as much of the interesting part of the graph as possible.
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In home folder (main calculator screen) press [Diamond][F2:Window]] to access Window configuration screen.
Press [F1] ( not mecessary now because the F1 page is open by default). In the F1 page of configuration screen set Xmin=-10,
Xmax=10
Ymin=-10
Ymax=10
Xscale=1.
Yscale=1.

OR
Press [Diamond][F2:Window][F2][6:ZoomStd] (Zoom Standard) to set all values as above.

If a graph is active (axes displayed, or part of a curve is showing) press [F2:Zoom][6:ZoomStd]
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The maximum and minimum are not working, when i put in the problem and it will give me the graph but when i use maximum or minimum it will give me the same answer on every problem

Hello,
When you are use the calculator to find a maximum or a minimum, you are supposed to give the calculator a range of values between which to search for i (interval where the max or min lies)
1.Look at the graph to locate approximately the position (the x coordinate) of the minimum.
2. Supply the left limit of x ( to the left of the minimum) Press [ENTER]
3498c8f.jpg 3. Supply the right limit of x (to the right of the minimum). Press [ENTER]
4a5a77d.jpg 3. Supply an estimate of the X-value of the minimum.

afc61ed.jpg
After a moment the calculator displays the X and Y values of the maximum. The better your estimate, the faster the maximum will be found.

d8247ba.jpg
Hope this will help you set your problem correctly.
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Ti-89 titanium

2nd and f6 or something...
make sure minimum and maximum values aren't mixed up!
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