Type an equation. Simplify your answer.
The equation of a circle is (x-h)^2+(y-k)^2=r^2. Since h and k are 0, we have x^2 + y^2=r^2. Since r= 5, r^2=25.
Thus, the equation is x^2 + y^2 = 25.
Good luck.
Paul
X^2 + y^2 = 5
SOURCE: Argument error whenever I type equations with variables.
Perhaps you have some data stored in the x variable.
With the calculator on, press [2nd] then the minus button. This brings up a list of all the saved data in the calculator. Look through the far left column of the list for x.
If you find x in the list, highlight x, then press F1, and then select delete.
Now it should work like normal.
SOURCE: how to simplify the equations in ti 84 ??
You cannot do it with this calculator. It does not have a Computer Algebra System (CAS). Try a TI89 Titanium, a TI 92PLUS, a TI 200PLT or a TI-Nspire CAS.
However, they may exist other programs on education.ti.com or ticalc.org. Search these sites and you may be lucky.
Testimonial: "thanks"
SOURCE: I am trying to solve imaginary number equations
I am afraid you cannot use the TI8xPlus family of calculators to solve linear systems in matrix form. In this calculator, matrices must have real coefficients.
You can however separate (expand) the problem into a linear system of 4 equations in 4 unknowns and try to solve it with the calculator.
Similarly, you rewrite the second complex equation substituting a+ib for X and c+id for Y, then expand the binomial products, gather the real parts on the left together, and the imaginary parts on the left together. After that you equate the real part on the left to the real part on the right, and do the same for the imaginary parts.
If I did not make mistakes during the expansions and the gathering of terms you should get the following equation
-(8a+8c+10d) +i*(-8b+10c-8d) =0+i*0 from which you extract an equation for the real parts, -(8a+8c+10d)=0 and another for the imaginagy parts i*(-8b+10c-8d) =i*0
If I did not make mistakes (you should be able to find them, if any) your system of two linear equations with complex coefficents has been converted to a system of 4 linear equations with real coefficients.
8a-15b-8c=10
15a+8b-8d=0
8a+8c+10d=0
-8b+10c-8d =0
Now, you can in theory solve this system with help of the calculator, to find a, b, c, and d. When these are found, you can reconstruct the X and Y solutions.
Now get to work: Ascertain that my extracted equations are correct, then solve for a, b,c, and d, and reconstruct X and Y.
I am no seer, but my hunch is that this system is degenarate. I will not explain what that means.
SOURCE: How can I type in a radical expression and
Sorry to disappoint you. You can enter a radical by making use of the square root or the universal power [^] with fractionary exponent, but once you press the [ENTER] key, your expression is calculated and displayed as a decimal number.
By updating the OS to version 2.53MP, you will be able to manipulate fractions more easily than your current OS version, but no facility is provided for radicals.
SOURCE: How do I do a standard form equation on the
how to calculate sin 2 theta from fx-991ms calculator
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