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Rephrase the question please. It makes no sense, in particular what are all those TIMES for?
Combine all the logs using the rule log_2(a)+log_2(b)=log_2(a*b)
You get
log_2((x-10)(x-3)/x)=2=log_2(4)
Thus
(x-10)*(x-3)/x=4
Convert it to a quadratic equation (x^2-17x+30=0). the solutions are x=2 and x=15. That should not be too difficult to factor out 5*2=30 -15-2=-17.
The LOG key on the keyboard gives you base-10 (common) logs while the LN key gives you base-e (natural) logs. If you want the log to another base you can use the logBASE function found in the catalog.
Absolutely. To take the logarithm base b of x, simply divide the logarithm of x by the logarithm of b. You can use either the common (base-10) or natural (base-e) log, as lojng as you're consistent. To calculate the log base 3 of 9, for example, calculate either log 9 / log 3 or ln 9 / ln 3
Calculate the log (base 10) of the number, then divide the result by the log (base 10) of the base. For example, to calculate the base-3 log of 9, calculate the log of 9 to get 0.954 . Divide that by the log of 3 (about 0.477) to get 2.0 . Since 9 is 3 squared, the log base 3 of 9 is 2, as we just calculated.
You can calculate the log to any base B by dividing the base-10 log by the log-base-10 of the base B. You can also calculate it by dividing the natural log by the natural log of B.
For example, to calculate the base-3 log of 10, calculate log(10) / log(3) or ln(10) / ln(3)
Look it's simple in the calculator the default base is 10 so when you input log 3 its log 3 base 10 so: maybe you know in math log x base y = log x / log y . So if you need log 3 base 3 its => log 3 / log 3 (by the way its 1)
It's 2*3=6 but about the base, you can't change it in the calculators the default base it's 10 so log x it's Logbase 10^x here some logs:
log x base y = log x / log y
log (x*y) = log x + log y
log (x/y) = log x - log y in your example log 9 base 3 = log 9 / log 3 etc. hope you get it, and it was helpful
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