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Width is 10 metres
Length is 12 metres
Derive an equation for area in the form of x
Area= length x width
120sqm = x(x-2)
120sqm = xsquared - 2x
Then apply to formula for solving a quadratic equation.
Hope that helps.
A rectangle is a two-dimensional figure and doesn't have a volume. It has an area equal to length times width. A rectangular prism has a volume equal to length times width times height.
There isn't a single formula for solids of different shapes. For a right solid with a rectangular base - volume is base area x heightSimilarly for cylinder with a circular base - volume = base area x height (base area in this case is Pi x radius2).For a sphere - volume = 4/3 x Pi x radius3
The diameter of the circle is the diagonal of the rectangle use Pythagoras this rectangle is a made from two 3,4,5 triangles, so the diameter is 5cm, the radius will be 2.5cm don't forget the BODMAS ordering rule (Brackets of Division Multiplication Addition and Subtraction) Also rounding to 2 decimal places. This solution is based on all four corners of the rectangle touching the circumference of the circle.
Area of a circle is P (22/7) i x Radius (squared ^2) ====> 22/7 x 2.5cm ^ 2 ====> 22/7 x 6.25cm
TOTAL AREA of CIRCLE = 19.64 cm^2
Area of the rectangle is length x width ====> 4 cm x 3 cm
TOTAL AREA of RECTANGLE = 12 cm ^2
The remaining portion is the circle area minus the rectangle 19.64-12 = 7.64 cm^2
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Your field, terrain, figure has a particular form. For each form you have a formula that tells you how to compute the area enclosed. Read your book or your notes to know what formula to use. I cannot give you a formula because I have no idea about the shape of the figure nor its dimensions.
Now, having the formula at hand you can use your calculator to calculate the area. But, in order to obtain consistent values you must convert all dimensions to the same unit length: m, cm, km, inches, feet or what have you.
For example: You have a rectangle with LENGTH L=3.5 m, and a width W=20 dm (decimeters), you must convert the value in decimeters to meters, 20 dm=2 m. The area of you rectangle will be Area=L*W=(3.5 m)*(2 m)=3.5*2 m*m= 7 m^2
This lot does not have the form or a regular quadrilateral (rectangle, square, parallelogram, etc.)
So you cannot calculate its area, you have to know exactly the shape it has.
With polygons, one usually cuts them into triangles.
You have to cut it into two triangles,
measure the base and the height of each triangle,
use the area formula for the triangle ( area = heightX base/2)
After you calculate the areas of both triangles, you add them to get the area of the the whole lot in ft^2.
Using the conversion formula between acres and ft^2 which is 1 acre=43560 ft^2, you divide the area of the lot in square feet by the number 43560 ft^2 and express the result as a percentage or a fraction .
Virtual keyword allows the program to dynamically decide which function to call. That is, when derived class is inherited from a base class the function in derived class can perform a completely different action from the one in Base class. Hence the function call via a pointer or reference maps to different functions based on the type of the object.
Abstract base class is used, so that anyone who is inherting from this class should implement that interface. Because the base class may not have a meaningful implementation for that interface. For example to design a program for computing area of different shapes like rectangle, triangle, hexagon etc. base class can be thought of as Shape. In addition the base class can be made abstract by declaring Area to be a pure virtual function. Then the different shapes like Rectangle, Triangle classes can inherit from Shape and implement Area interface based on their formulae.
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