Circle equation - Office Equipment & Supplies

B. Equation of a circle is (x-a)^2 + (y-b)^2 = r^2, where (a,b) is the centre of the circle and r is the radius.

A. The equation of a circle is (x-a)^2 + (y-b)^2 = r^2, with (a,b) being the centre of the circle and r being the radius.

Good luck,

Paul

x^2 + y^2 = 5

Use the conics utility
Scroll until you find the equation of a circle and an image, Select it, then enter the coefficients.

Use the conics utility
Scroll until you find the equation of a circle and an image, Select it, then enter the coefficients.

First, I graphed the lines and the point using Desmos.com.

I noticed that the two lines are perpendicular to each other and the point (1,-1) appears to be on the right side of the circle, on a line parallel to 3x -4y-10=0. The equation of this line is y= 3/4x - 1.75. The y-intercept is -1.75. Now we have two points on the opposite sides of the circle, (1, -1) and (0,-1.75). The midpoint formula will give you the centre of the circle and the distance formula will provide the radius.

Let me know if you have any questions.

Good luck.

Paul
Desmos Beautiful Free Math

A circle is not a function and cannot be graphed in the regular y=screen. You can graph a circle in parametric mode.

To graph a circle in the regular y= screen, you have to graph it in 2 lines on the y= screen. I assume you've solved for y and gotten a square root equation. Remember a square root can be positive or negative. In line 1 of y= screen graph what you've been graphing and then graph the same equation in line 2 but with a negative in front of the equation. You'll get something that looks like an oval since the calculator screen is rectanglular. To make it look more circular (both parts aren't going to connect), press zoom and then select #5 (square).

assuming the question is what is the circle equation?
and if (-2,2) is the center of the circle
the equation should look like this: (x+2)^2+(Y-2)^2=R^2

And now only R is needed.

given 2x-5y+4=0 equation of line perpendicular

we can rearange the equation to be y=(2x+4)/5
from that we can see that the slope of the line is 2/5
And from the fact of perpendicular line we can say that the slope
of the radius line is -2/5.

The motivation now is to calculate the distance between the center of the circle to the cross point of the radius with the line perpendicular

For that we would calculate the radius line equation and compare it to the equation of line perpendicular

As mentioned earlier the slope of the radious line is -2/5.

So the equation is y=-2/5x+b and b can be calculated by using the center of the circle coordinates

2= - (2/5)*(-2)+b ------> b=2-4/5=1.2
radius equation is y=-(2/5)x+1.2

Now the cross point is calculated by comparing the equations:
-(2/5)x+1.2=(2x+4)/5 --> -2x+6=2x+4 --> 4x=2 --> x=1/2 --> y=1

So the cross point is (1/2,1).

The distance between the points is calculated by the following
Formula:

R=SQR(((1/2)-(-2))^2+(2-1)^2)=SQR(2.5^2+1^2)=SQR(6.25+1)=
SQR(7.25)

Therefore the circle eq is (x+2)^2+(Y-2)^2=7.25

There is a circle on the door. When you have loaded the dishes, pour the detergent on the door to fill the circle and close the door.

You have two methods for drawing a circle on the FX-9750GPlus.

1. Use the Conics graphing: The general equation of a circle is aX^2 + aY^2 + bX+cY+d=0
2. Use the function graphing. But before you can do that you must transform the general equation (above) in such a way that you can write it as Y^2= X^2+EX+F. From this you can find the two branches Y1=SQRT(X^2+EX+F) and Y2=-SQRT(X^2+EX+F)