SOURCE: steps in solving matrix on my ti 89 calculator.
I assume you are speaking of solving a system of equations with a number of unknowns. If not, please correct me. Here's an example in practice:
If you have a system of 3 equations with 3 unknowns, you would set up your matrix so that the coefficients of each variable for a particular equation are on one row. So, given equations x + y + z = 0, 2x + 3y - 4z = 1, x + -z = -1 you would type the following into your calculator: [[1,1,1,0][2,3,-4,1][1,0,-1,-1]] and press enter to make sure you typed it correctly. notice that in the third row there is a zero, since we have zero time y for the third equation. Then row-reduce the matrix (2nd > 5 > 4 > 4 or in the CATALOG as rref). You should get out the matrix [[1,0,0,-1][0,1,0,1][0,0,1,0]]. This says that x=-1 y = 1 z=0 since my first column contained the coefficients for the x variable, the second for the y variable, and the third for the z variable. The last column contains the solution, the part on the other side of the equals sign.
Hope this helps! For more reading (from someone else; I just made this one up), check out the Wikipedia articles on Gaussian elimination and Systems of linear equations
SOURCE: I am trying to solve
The distributions do not exist on the TI 89 Titanium. But you can download an application from the education.ti.com website. It is called tistale.89x. Here is the link to it.
SOURCE: solve() gives me wrong answer.
For the first problem you have to type: solve(-20^2=12^2+(2*X*(-5-3)),x)
Also, make sure you use the (-) key on the position number 5, just to the right of the decimal point and not the - key and on the number 3 you have type regulary subtraction - key
Answered: Stevan Milanovic
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Usually answered in minutes!
That depends on what you're trying to solve. Would you care to give some details?
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