Find all stationary points of y=(x-2)^4 - Texas Instruments TI-89 Calculator

recheck the valve clearance when the engine is hot if it is hydraulic operated then thee will be an auto adjustment but it should be around .010 " when stationary and hot

1) Copy following link:
http://waterheatertimer.org/Paragon-timers-and-manuals.html#7000
http://waterheatertimer.org/images/Paragon-4000-378.jpg

2) 7000 series is same as 4000 series except 7000 series is 7 day, and the stationary pointer on 7000 series is pointed at 9 o'clock position

3) Add a comment and include model and brand timer for clarification.

If you need further help, I’m available over the phone at https://www.6ya.com/expert/gene_9f0ef4df2f9897e7

T104 pointer is stationary and is supposed to be pointed straight down, assuming timer is installed in vertical position.
Move pointer until it points straight down and apply bit of super glue, or just remember correct location.
Copy following link for detailed information:
http://waterheatertimer.org/pdf/How-to-operate-and-set-T104-timer.pdf

If you need further help, I’m available over the phone at https://www.6ya.com/expert/gene_9f0ef4df2f9897e7

The time pointer is supposed to be stationary.
On T104 timer the pointer is stationary pointed downward at 6:00 position. So you can move it so it is pointed straight down and add a bit of super glue where pointer meets stem.
Copy following link for instructions how to set T104 timer:
http://waterheatertimer.org/pdf/How-to-operate-and-set-T104-timer.pdf

If you need further help, I’m available over the phone at https://www.6ya.com/expert/gene_9f0ef4df2f9897e7

There is only one stationary point for the function y(x)=((x-1)^(1/3))*((x+2)^(2/3)) and it is pointwith coordinates x=0 and y=-1.5859

At first, first derivation is y'(x)=x/((x-1)^(2/3))*((x+2)^(1/3)) and we obtained that y'(0)=0. Then we can find second derivation of the function and for value x=0 we could concluded that y''(0)>0. In this stationary point it is minimum value of the function.
Finally, at the points x=-2 and x=1 we have so called critical values for this function.
See captured images below

1. Second derivation for y(x)



2. Graph y(x)



3. Enlarged detail of the graph y(x)

Thank you for including timer model number.
Stationary pointer is pointed at 6:00 position on T100 series timers.
Pointer is not functioning part of timer mechanism except to point location for current time.

Open following links for resources:
http://waterheatertimer.org/images/Stationary-pointer-a2-415.jpg
http://waterheatertimer.org/pdf/How-to-operate-and-set-T104-timer.pdf
http://waterheatertimer.org/How-to-wire-T104-Intermatic-timer.html#T101

If those are the partial derivatives, then the stationary point should be (0,0). Because if you set the partial derivatives to zero and solve for x and y then the only solutions are x=0 and y=0.

See captured image below

The best method is to be stationary when changing. When done stationary the disengaugement usually happens without delay. If you are moving when changing take your foot off the throttle and it should disengauge.

The silver pointer arm is supposed to be stationary.
Part is not sold separately.
T100 series, the stationary pointer is pointed at 6:00 position.
Sprinkler timers, the pointer points at 7:00 position.
To set timer, rotate dial until current time lines up with stationary pointer.
Open following link for troubleshoot checklist
http://waterheatertimer.org/How-to-troubleshoot-Intermatic-timer.html