Is there an Avogadro's Number Shortcut - Texas Instruments TI-84 Plus Silver Edition Graphic Calculator

6 . 0 2 2 1 4 0 9 Exp 2 3

For more about the number, see Avogadro constant

Don't know if you have tried this, but it might help.

Create a scan to PC profile
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Good luck.

Look for a key that may be marked as X to power y, or Y to power x or just a caret [^]. However to enter a power of 10 such as in the Avogadro Number 6.02*10^23, scientific calculators have a specific key marked EE (enter exponent?) on TI's or x10^x on Casios.
When you use the EE key no 10 should appear: meaning to enter 6.02*10^23 you type in 6.02 followed by [EE] then 23. Press = to display the number. Th e EE key is a shortcut for *10^

Sorry, but there is nothing wrong with the exponential notation on your calculator. There is however a misunderstanding from your part on the priority rule of operations.
The sequence 0.030377/6.022x10^23 is interpreted as (0.030377/6.022)x10^23 while you wanted 0.030377/(6.022x10^23), dividing by Avogadro's Number.

How to fix it. Enter the power of 10 exponent (10^23) using the EE key. In other words Avogadro's Number should be typed in as 6.022 [EE]23. If you do not have the EE key you must use parentheses to enclose the whole number (6.022x10^23) or use the division key twice /6.022/10^23
On a calculator a sequence a/bxc where both operations have the same level of priority is executed from left to right.

Relative atomic mass of gold M(Au)= 196,96. To find the numbers of mols in the gold ring with mass m=10,6 g you have to simply calculate n=m/M and after that to multiply n with Avogadro's constant Na=6.022exp23. Final result is 3.24exp22 atoms. See captured image

The problem is how to enter the number on the calculator. after it is typed in, you can use in any kind of operations.
To enter Avogadro's number you enter the mantissa 6.02, then you press the [10^X] key then the exponent 23
The [10^X] is on the second row of keys below the [1/x] key. See picture.

6.02 [10^X]23 [=]

It should not, unless you entered it the wrong way. Use the key marked [^] or [X^y] or [Y^x].
It is none of my business but I think you are trying to type in Avogadro's number. If that is the case then you should use the [EE] key to enter the power of 10.
Type 6.022 [EE]23 (Notice that there is no 10 to enter; the EE key is a shortcut for [*10^ ] .)

1 Look up the formula for the aluminum acetate.
2 Count the number of Hydrogen atoms per molecule: Call that nH.
3 Dividing 2.24*10^22 by nH you get the number of molecules of acetate.
4. Divide that number by Avogadro's Number to obtain the number of moles required.
5. Multiply the number of moles by the molecular mass of the aluminum acetate (look it up or use the periodic table to calculate it), you will get the mass of aluminum acetate that contains 2.24*10^22 hydrogen atoms.

The "problem" is not how to calculate with numbers expressed in Scientific Notation but how to enter a number given to you in scientific notation. Once the number is entered you do not have to do anything special. If you have to multiply it use the (x) button. to add it use the + button, etc.

How to enter a number in scientific notation.

Type in the mantissa (example 6.022)
Press the [X10^x] at the bottom of keypad.
Enter the exponent (example 23)
with this example you will have entered Avogadro's number 6.022x10^23
Other example
1.6 [X10^x] (-) 19 enters the electron charge in Coulombs. The exponent is negative that is why you press the change sign key (-).

Hello,
Use the [x10 to x] key, on the bottom row, between [.] and [Ans].
You can store it in a variable (A, B, C or D). You can do that as follows

6.022214199[ x10 to x] 23 [SHIFT] [STO] D stores it in varaible D.

The Avogadro number (Na) is already in your calculator, it is one of the 40 scientific constants, under #24

To display it on screen
press [SHIFT][7] (CONST)
Screen Displays CONSTANT Number 01 tilda 40.
In the space at the bottom right [_ _ _ _] you enter 24. Screen displays Na. Press [=] to enter it in Ans memory so you can use it.

Hope it helps.