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Solvei Posted on Sep 03, 2013
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Scrolling sideways I'm solving a matrix. I put it in rref, but the answer column is off the screen to the right, and I can't figure out how to scroll over to it.

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k24674

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  • Texas Instru... Master 8,093 Answers
  • Posted on Sep 27, 2013
k24674
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Usually the right arrow allows you to move cursor to the right.

1 Related Answer

k24674

  • 8093 Answers
  • Posted on Jan 21, 2012

SOURCE: rref for 4X4 matrix does not answer correctly

To make sure that the calculator is misbehaving, I suggest that you create a simple 4X4 matrix, that is not singular, and calculate it reduced row echelon form by hand, then use the calculator to perform the reduction. You can also generate a random 4x4 matrix and calculate the rref forms by hand and with the calculator. If the calculator is defective, try to upgrade the OS. If it is still defective, well, the deck is stacked aaginst you. It may then be time to get another one or to send it for repairs.

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Rref for 4X4 matrix does not answer correctly

To make sure that the calculator is misbehaving, I suggest that you create a simple 4X4 matrix, that is not singular, and calculate it reduced row echelon form by hand, then use the calculator to perform the reduction. You can also generate a random 4x4 matrix and calculate the rref forms by hand and with the calculator. If the calculator is defective, try to upgrade the OS. If it is still defective, well, the deck is stacked aaginst you. It may then be time to get another one or to send it for repairs.
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Steps in solving matrix on my ti 89 calculator.

I assume you are speaking of solving a system of equations with a number of unknowns. If not, please correct me. Here's an example in practice:

If you have a system of 3 equations with 3 unknowns, you would set up your matrix so that the coefficients of each variable for a particular equation are on one row. So, given equations x + y + z = 0, 2x + 3y - 4z = 1, x + -z = -1 you would type the following into your calculator: [[1,1,1,0][2,3,-4,1][1,0,-1,-1]] and press enter to make sure you typed it correctly. notice that in the third row there is a zero, since we have zero time y for the third equation. Then row-reduce the matrix (2nd > 5 > 4 > 4 or in the CATALOG as rref). You should get out the matrix [[1,0,0,-1][0,1,0,1][0,0,1,0]]. This says that x=-1 y = 1 z=0 since my first column contained the coefficients for the x variable, the second for the y variable, and the third for the z variable. The last column contains the solution, the part on the other side of the equals sign.

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Solving matrix

Go to your matrix button and enter a "3x4" matrix.

Then enter it as follows:

-3 4 5 7
4 3 2 9
-5 5 3 -10

Then exit out and go to "2nd->matrix->math->rref(". Then press enter.

Your screen should look like this:

rref(

Then go to matrix and select your 3x4 matrix, press enter and close it with a parathesis. Your screen should look like this:

rref([A])

Press enter and the screen should say this:

1 0 0 2
0 1 0 -3
0 0 1 5

So,
x=3
y=-3
z=5

Hope this cleared up the confusion!

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