Question about Texas Instruments TI-84 Plus Calculator

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Err: bound When I try to graph and find my intercepts, my calc will not go past the part where it says "second curve?" also when i try to use the calc feature to find my intercepts it says "err:bound"...i have not changed anything since the last time I used my calc a month or so ago and I did not have any problem completing these tasks previously...

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  • 8,081 Answers

You may be making a confusion between intercepts and intersections. Intercepts are crossing of the axes. Intersections are between two curves: You need to have two curves graphed. You choose the first curve by selecting it (Up or Down Key), and then the second one.

Posted on May 20, 2018

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Posted on Jan 02, 2017

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SOURCE: ERR:SYNTAX

try to change the mode to function otherwise im stumped

Posted on Feb 16, 2009

  • 1 Answer

SOURCE: my graphing calculator won't graph anything

Go to your stat plot screen, and select option 4 (PlotsOff), Press Enter, and try to plot a normal graph again

Posted on Jul 15, 2009

  • 88 Answers

SOURCE: err: no sign chng

When you get the sign change error it is either that you have mixed up the left bound and the right bound or that you are marking the left and the right bound both above the x-axis or both below the x-axis. That's why you get the sign change error. Your range values must have different signs.

Posted on Aug 29, 2009

  • 7 Answers

SOURCE: When graphing says ERR: INVALID DIM 1:Quit

You have two lists that don't agree in length.

Solution 1 (easy)

Press [y=] and look at the top line - one of your Plots is highlighted.
Move the arrow to the highlighted one, press enter to get it un-highlighted.

Solution 2 (permanent)

Press [STAT] - EDIT: [1] to edit your lists. Go to the bottom of the lists and see which one is the longest. Delete (DELETE, not clear) the "extra" entries in the longest list until all lists are the same length.

Posted on Oct 06, 2009

  • 8081 Answers

SOURCE: WHen trying to graph anything, ERR: INVALID DIM

Hello,
The easiest and quickest way to start graphing is to reset the RAM. Press [2nd][MEM][7:Reset][1:All Ram][2:Reset], then [CLEAR] to clear the RAM Cleared Message and go to the main screen.
Hope it helps.

Posted on Oct 16, 2009

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2 Answers

Log(x+2)+log(x+3)=7-x How to intersect with TI-84


Press Y=
On the Y1 line enter the expression LOG(X+2)+LOG(X+3) by pressing
LOG ALPHA [X] ) + LOG ALPHA [X] + 3 )
On the Y2 line enter the expression 7-X by pressing
7 - ALPHA [X]
Press GRAPH to see the graph. To see where they intersect, press 2ND [CALC] 5. See "First curve?" in the lower left. Use up/down-arrow to select one of the two curves and press ENTER. See "Second curve?" in the lower left. Use up/down-arrow to select the other curve and press ENTER. See "Guess?" in the lower left. Press ENTER. The calculator will show the coordinates of the intersection.

Sep 19, 2012 | Texas Instruments TI-84 Plus Calculator

2 Answers

Minimum or maximum value of a parabola


Follow these steps: graph the parabola and after that 2nd then CALC keypad. To find extreme value of the function select 3: min or 4: max options. Select the function and set left bound, right bound(using left and right arrows) by pressing ENTER. You can see images bellow for all these steps for the y=-2x^2+5x+3

1. step: graphing parabola
3_9_2012_7_34_06_pm.jpg

2. step: left or lower bound
3_9_2012_7_36_01_pm.jpg

3. step: right or upper bound
3_9_2012_7_37_33_pm.jpg

4.step: extreme value of the function
3_9_2012_7_39_04_pm.jpg

Mar 08, 2012 | Texas Instruments TI-84 Plus Silver...

1 Answer

When I try to find Intercept on my graph I : [2nd]Trace [Enter] (for first curve) [Enter] (for second curve) but nothing happens. It still asks me for second curve. I move the point to diffrent...


There seems to be a confusion between two terms: intersection of two curves and y-intercept, or x-intercept.
When you press [2nd][TRACE] you are accessing the CALCulations menu for the graphics. The [1:calculate ] sub-menu gives the value of y for a given value of x. The first curve taken is the one in Y1=. If you want to find the value of y on a second curve for the same value of x, you use the Up Arrow or Down Arrow. (Use Up Arrow or Down Arrow to cycle through the curves.)
The sub-menu [5:Intersect] allows you to find a point where two curves intersect (cut one another). The calculator starts on the first curve (Y1=) and asks you to select the second curve. At this point you use the Up or Down arrow to jump tho the next curve. Then you will be asked for a guess.
First, know what you want and do not confuse interCEPT with interSECT

Jul 05, 2011 | Texas Instruments TI-84 Plus Calculator

1 Answer

Why wont my calulator let me enter a second guess when finding the intercept on my graph?


To find the intersection (read interSECTION) of two curves you are prompted once for an initial guess. If the calculator does not find the intersection point , or if there are more than one intersection points, you have to restart the procedure.
For your information, the interCEPT (or y-intercept) is the ordinate of the point where a curve cuts the y-axis. It is easy to mistake one word for the other. They are not synonymous.

Jul 05, 2011 | Texas Instruments TI-84 Plus Calculator

1 Answer

I need to find decreasing and increasing intervals and I dont know how to do this on my TI 83


While your TI-83 plus cannot explicitly find increasing or decreasing intervals, it can find the minimum(s) and maximum(s) of a function.
Press the "Y=" button.
Enter the equation in "y=" format into the first open equation.
Press the "GRAPH" key.
If the maximum and minimum of the curve are not shown in the window it has, press ZOOM->0.
Press 2ND->CALC (under the "TRACE" key).
Press 3 if you are trying to find a min, 4 if you're trying to find a max.
It will ask for bounds. Enter a left and right bound by looking at the graph itself and choosing a left bound that is clearly to the left of the min/max, and a right bound clearly to the right of the min/max.
Then it will ask you to guess a value. You can skip this step by pressing ENTER instead of entering a value.
It will calculate the value. To find increasing/decreasing intervals, just know that every interval with a minimum as the left bound and a maximum as the right bound is increasing, and vice versa.

Feb 25, 2011 | Texas Instruments TI-83 Plus Calculator

1 Answer

I DO NOT KNOW HOW TO FIND THE MINIMUM ON A GRAPH WHEN IT IS ON MY CALCULATOR


After you have drawn your graph, press [2nd][TRACE] to access the (CALC) menu
945fb0b.jpg
In the above screen (on your calculator) press [3:minimum]
You will be promped for the lower bound of the domain where you think the minimum lies.
5d2b86d.jpg
Notice the dark spot on the curve near the X axis: That is what the calculator suggests as a lower bound. Since it is rather close to the minimum you are well advised to select this as a lower bound. To accept it press [ENTER].
You are then prompted for the right bound. Be ready to move the cursor to the right side of the minimum. That is what I had to do to get the following screen. Notice the mark on the curve at X=4.7
4263d02.jpg
Press [ENTER] to accept or type in a reasonable value.
The calculator prompts you for a guess. Enter a value that lies in the interval [left bound, right bound] and press [ENTER]
a07ff44.jpg

As you can see, I entered value X=3 and pressed [ENTER]
94af57a.jpg
Here is the result. Enjoy
148f529.jpg

If you have to look for a maximum, the procedure is the same, except that at the begining of the search you select [4:maximum] on the first screen capture (see above.)

Feb 09, 2010 | Texas Instruments TI-83 Plus Calculator

1 Answer

My calc doesn't graph. Once I click graph it says ERR: Invalid Dim, and my only option is Quit. What do I do??


You're probably trying to graph a function that does not involve stat plot features. You can correct this by turning off the stat plot features. Press "2ND" "STAT PLOT" and then select 4:PlotsOff.

If this isn't the problem, try posting the function(s) you're trying to graph, as well as the window settings.

Feb 07, 2010 | Texas Instruments TI-84 Plus Silver...

1 Answer

Solve for x-intercept and graph:f(x)= -x^2 + 2x - 1


Graph the function then use the trace function to locate the point(s) where two curves intersect. In your case one of the curves is the X-AXIS.

See the screen capture to learn how to use the trace functionality.
d17e4f2.jpg
8bb4dda.jpg

Feb 05, 2010 | Casio FX-7400G Plus Calculator

1 Answer

My TI 84 Plus Caluclator


Hello,
The function Intersect from the CALCULATE menu finf the coordinates of a point at which two or more curves intersect.
To use it:
1. Draw the functions.
7036100.jpg
2. Press [2nd][CALC][5:Intersect]

4c21f92.jpg

The cursor is on one of the curves. Read the equation top of the screen. If it is one of the curves you want press [ENTER]. The cursor jumps to another curve (in this case the only other curve).
f75e725.jpg
Read the equation on top of the screen to verify thst it is the correct one. Press [ENTER]. The calculator asks asks for a guess of the coordinates of the intersection point.
ee9cd29.jpg

As the intersection point is to the left of the current cursor position, use the left arrow to move cursor closer to the point.

d22f78b.jpg
Press [ENTER], and wait for the solution. Here it is.
2b043d0.jpg

In your question you talk about y intercept. If you want to calculate the ordinate of the point where a curve intersects the Y-axis, it is more efficient to use the [2nd][CAL][1:Value] selection.
0a11a73.jpg
You enter X=0 and press [ENTER]. The cursor jumps on the first curve (Y1=) an gives you the y-intercept.
7420d8f.jpg
Notice the position of cursor on graph. The y-value at the bottom is its ordinate.
To get the y-intercept of the second curve, leave the cursor on y axis and press the DownArrow. Cursor jumps to tthe second curve.
Since the X=0 is still stored, the value of y is displayed directly.

b14da69.jpg

Hope it helps.

Oct 27, 2009 | Texas Instruments TI-84 Plus Calculator

1 Answer

Err: no sign chng


When you get the sign change error it is either that you have mixed up the left bound and the right bound or that you are marking the left and the right bound both above the x-axis or both below the x-axis. That's why you get the sign change error. Your range values must have different signs.

Aug 19, 2009 | Texas Instruments TI-84 Plus Silver...

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