Question about Texas Instruments TI-84 Plus Calculator

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Divisors of a number on the Ti-84 plus.

How do I find the divisor pair list on the Ti-84 plus? For example, 20 would be 1,20 or 4,5. I did this before using the y= function. y1 and y2 show the divisors on the table and x=20. It also involves using the the table set up and some other button. Thank you for helping me. :0)

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6 Suggested Answers

6ya6ya
  • 2 Answers

SOURCE:

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Posted on Jan 02, 2017

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Mattimeo310
  • 30 Answers

SOURCE: table problem

I have had the same problem luckily i figured out what to do. 1. press the apps button 2. then there should be an unwanted app(it was the only one on mine) 3. pick it and hit enter 4. go to uninstall on the top of ur screen problem solved!!!! hope this helped

Posted on Oct 02, 2007

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  • 11 Answers

SOURCE: error :invalid DIM

This is my first post on this site, but I've had friends at school ask me about this. Apparently I'm like a calculator genius or something...

One solution I know of is clearing the RAM. Sounds strange, doesn't it? But it fixed three different calcs.

Be sure to back up or archive important data before doing this.

Posted on Oct 21, 2008

rockitman187
  • 2559 Answers

SOURCE: Can't find the % button on TI-84 plus :(

Just hit the 2ND key and the 0 (catalog key)scroll down to percentage or just divide the answer by 100.

Please rate this a fixya

63c07eb.jpg

Posted on Feb 13, 2009

  • 8081 Answers

SOURCE: I am trying to solve imaginary number equations

I am afraid you cannot use the TI8xPlus family of calculators to solve linear systems in matrix form. In this calculator, matrices must have real coefficients.
You can however separate (expand) the problem into a linear system of 4 equations in 4 unknowns and try to solve it with the calculator.

  1. define X = a+i*b
  2. Define Y=c+i*d
  3. Rewrite the first equation substituting a+i*b for X and c+i*d for y.
  4. Gather all real terms together, and all imaginary terms together on the left.
  5. You will have (8a-15b-8c) +i(15a+8b-8d) = 10 +0i
  6. This equation can be split into two equations by saying that
  • the real part pf the left member is equal to the real part of the right member, this gives 8a-15b-8c=10, and
  • the imaginary part of the left member is equal to the imaginary part of the right member, this gives 15a+8b-8d=0
Similarly, you rewrite the second complex equation substituting a+ib for X and c+id for Y, then expand the binomial products, gather the real parts on the left together, and the imaginary parts on the left together. After that you equate the real part on the left to the real part on the right, and do the same for the imaginary parts.

If I did not make mistakes during the expansions and the gathering of terms you should get the following equation
-(8a+8c+10d) +i*(-8b+10c-8d) =0+i*0 from which you extract an equation for the real parts, -(8a+8c+10d)=0 and another for the imaginagy parts i*(-8b+10c-8d) =i*0

If I did not make mistakes (you should be able to find them, if any) your system of two linear equations with complex coefficents has been converted to a system of 4 linear equations with real coefficients.

8a-15b-8c=10
15a+8b-8d=0
8a+8c+10d=0
-8b+10c-8d =0

Now, you can in theory solve this system with help of the calculator, to find a, b, c, and d. When these are found, you can reconstruct the X and Y solutions.

Now get to work: Ascertain that my extracted equations are correct, then solve for a, b,c, and d, and reconstruct X and Y.
I am no seer, but my hunch is that this system is degenarate. I will not explain what that means.

Posted on Feb 11, 2010

  • 24 Answers

SOURCE: I have issues turning on my TI-Nspire using TI-84 Plus SE keypad

i would say use the normal key pad or send it in to T.I to fix.

Posted on Mar 12, 2010

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1 Answer

My 'X=" isn't showing up above the "Y="


When you push the button [Y=] to open the function editor you will see Y1=,Y2= etc. That is the default behavior. By default the graph type is FUNCTION (y=f((x). However there are other graph types, for instance PARAM, POLAR, and SEQUENCE.
For Parametric graphs, you need two functions x as a function of t and y as a function of t. In this case, when you open the function editor, you will see pairs of functions x1(t), y1(t), x2(t), y2(t), etc. Both x and y functions of the pair must be supplied.

So if your x= function is not showing, then you must open the MODE screen, and scroll down to reach the 4th line that says FUNC, PAR, POL, SEQ. Highlight PAR and press ENTER. You do that only if you want to graph parametric functions.

Nov 04, 2011 | Texas Instruments TI-84 Plus Silver...

1 Answer

When I enter a function in Y1 and Y2, my calculator only graphs y1. How can I see both functions?


You must have used the Transfrm application before. It stays in memory, and prevents you from drawing more than one function. You must unload it from RAM.
  1. Press APPS
  2. Use the Up or Down arrow to scroll along the list pf APPS.
  3. Find Transfrm
  4. Highlight it and press ENTER
  5. In the new screen that is displayed select the option to UNINSTALL and press ENTER.
  6. Go to the Y= editor and type in your functions.

May 15, 2011 | Texas Instruments TI-84 Plus Calculator

1 Answer

How to graph a fog problem


To graph a f o g problem input the g function for y1. Then for y2 input the f function, anywhere there is an x (or whatever your variable is) put y1 instead.

Mar 08, 2011 | Texas Instruments TI-84 Plus Silver...

1 Answer

What is the equation of the pair of points (-5,-8) and (-3, -1)


The site seems to eat the plus signs I enter, so I will use PLUS to symbolize addition.

To find the equation of the straight line (
y = a*x PLUS b) that passes through two points P1(x1,y1) and P(x2,y2) , you need to use
1. the coordinates of the points to calculate the slope a (gradient) as a=(y2-y1)/(x2-x1)
2.
Replace the calculated value of a in the equation and write that one of the points ( P1(x1,y1) for example) satisfies the equation. In other words y1=a*x1 PLUS b.
Here y1 and x1 are known values, a has been calculated, and only b is still unknown. You can now use the equation
y1=a*x1 PLUS b to calculate b as
b=(y1-a*x1)

Example: Equation of the line through (1,5) and (3,6)

Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5, x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2
The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=(1/2)*3 PLUS b.
Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5
Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

I trust you can substitute you own values for (x1,y1, x2,y2) to duplicate the calculations above.

Jan 27, 2011 | Texas Instruments TI-84 Plus Calculator

1 Answer

Find an equation of the line containing the given pair of points (1,5)and(3,6)


Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5, x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2
The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=3/2 PLUS b.
Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5
Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

Oct 20, 2010 | Texas Instruments TI-84 Plus Calculator

1 Answer

Find an equation of the line containing the given pair of points (-6,0) and (0,1) what is the equation of the line? y=


Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=1, y1=0, x2=0, and x1=-6. You should get a=(1-0)/(0-(-6))=1/6
The y-intercept is the y-cordinate for x=0. Its value is 1.
The equation is then y=(x/6) 1.

Oct 18, 2010 | Texas Instruments TI-84 Plus Calculator

1 Answer

I am trying to graph to evaluate each expression. how could i do it on the calculator(ti-83) a:(f+g)(0) b)(f-g)(-1) c)(fg)(1) (d)(f/g)(3()


Let us see if I understand what you want to do. You have two functions f and g. With f and g you create four functions,
  1. f+g, which you want to evaluate at 0
  2. f-g, which you want to evaluate at -1
  3. f*g, which you want to evaluate at 1
  4. and f/g, which you want to evaluate at 3
If that is not what you intend to do, then I am sorry to I that interpreted incorrectly and you will have to post a comment with more information.
If however I did understand what you want to do, then there is a simple way to achieve this
  1. In the [Y=] function editor, enter Y1 and Y2
  2. In your mind decide which one represents f(x) and which represents g(x), probably f(x)=Y1(x) and g(x)= Y2(x)
  3. Validate each one by pressing [ENTER]
  4. Do not worry about graphing the function.
  5. Press [2nd][QUIT] to return to main calculator screen
  6. Enter a value (for example 5) and store it in variable X; to do so you press 5 [STO->][X,T, theta,n] [ENTER]
  7. To calculate f(x)+g(x) or (f+g)(x) on the command line in main calculator screen
  • Press [VARS][=>][Y-VARS][1:Function][1:Y1][ENTER]. Main calculator screen echoes Y1
  • Press [+]. Screen shows Y1+
  • Press [VARS][=>][Y-VARS][1:Function][1:Y2][ENTER]. Main calculator screen echoes Y1+Y2
  • Press [ENTER] to obtain the value of f+g at X=5
As you can see, if you want a different operation f-g, f*g, or f`/g for a different value of X, you will have to repeat steps 6 and 7.

I am going to show you how to create a small program that will perform all the 4 operations in sequence, each time asking you for the value of X you want to use. If you are not interested, you can ignore what follows. I remain convinced that it will be helpful for other visitors.

Creating a simple program

Press [PRGM]
Use arrow to highlight [NEW]
Press [ENTER]
Screen displays
PROGRAM
Name= with alpha cursor blinking
Type in the name, for example FOPG ( meaning F operation G) or anything else. Do not use a keyword (reserved command of the TI84Plus) These are what you find in the [CATALOG].

ddae385.jpgac147eb.jpg

The top line on each screen capture is inserted by the program editor after you choose the name. The last line of first screen is the the same line as the second line on 2nd screen. It must not be entered. The colon : is supplied by the program editor. It is the beginning of an instruction.

There are only to commands that are repeated here: Disp and Prompt

Disp orders the program to display
  1. a message (what is between the quotation marks) or
  2. the result of a calculation: Y1+Y2, Y1-Y2, Y1*Y2, or Y1/Y2
Prompt X will display X=? and the blinking cursor. You are supposed to enter the desired value of X and press [ENTER].
The Disp and Prompt command are accessed through the command catalog by pressing [2nd][0] (CATALOG) then scrolling along the list of commands to find the one needed. Shortcuts are possible (see below)

How to key in the program steps within the program editor
: Disp "F+G"

Press [2nd][0] (CATALOG) [X^-1](D) [Scroll Down [till...] Disp
Press [ENTER]. Editor shows :Disp
Press [ALPHA] [+] ("). Editor shows :Disp "
Press [ALPHA][COS] (F). Editor shows :Disp "F
Press [+]. Editor shows :Disp "F+
Press [ALPHA][TAN] (G). Editor shows :Disp "F+G
Press [ALPHA][+] (") Editor shows :Disp "F+G"
Press [ENTER] to validate instruction
Calculator inserts a new line :

: Disp Y1+Y2
Press [2nd][0] (CATALOG) [X^-1](D) [Scroll Down [till...] Disp
Press [ENTER]. Editor shows :Disp
Press [VARS][=>][Y-VARS][1:Function][1:Y1][ENTER]. Editor shows :Disp Y1
Press [+] . Editor shows :Disp Y1+
Press [VARS][=>][Y-VARS][1:Function][1:Y2][ENTER]. Editor shows :Disp Y1+Y2
Press {ENTER] to validate instruction
Editor inserts a new line :


:Prompt X
Press [2nd][0] (CATALOG) [8](P) [Scroll Down [till...] Prompt
Press [ENTER]. Editor shows :Prompt
Press [X,T.theta,n] key. Editor shows :Prompt X
Press [ENTER] to validate instruction
Editor inserts a new line :

To save program
Once all instructions are entered, press [2nd][QUIT] to save program.

To run program


  1. Press [PRGM]
  2. Under the [EXEC] menu, the list of available programs appears.
  3. Type the number corresponding to the one you want to run ( FOPG) and press [ENTER].
  4. The main calculator screen displays prgmFOPG and blinking cursor.
  5. Press [ENTER] to make it run
  6. Enter a value of X and press [ENTER]
  7. Follow instructions.

Dec 21, 2009 | Texas Instruments TI-84 Plus Calculator

1 Answer

How do you use a plus or minus sign on a TI-84


Hi,
You cannot use the ± in the definition of a function. If you need to consider two alternatives, you have draw each function separately, one function as Y1 and the other as Y2. I just checked the catalog of commands, and there is no ±.

Hope it helps.
Thanks for using FixYa

Nov 19, 2009 | Texas Instruments TI-84 Plus Calculator

1 Answer

My calculator will only show one line/ t-table at a time... I cannot "turn on" both y1 & y2


Hello,
Sure you can. Values of Y1 and Y2 will be calculated for the same value of the independent variable. here is a screen capture taken with NO special configuration. Functions represented are Y1=2X, Y2=4X.

9ecc92a.jpg If you have a
Hope it helps.

Oct 01, 2009 | Texas Instruments TI-84 Plus Silver...

1 Answer

How can I get my calculator to highlight more than one function, to graph a circle for example?


Hello,

Suppose you want to draw the circle the equation of which is X^2+Y^2=4, a circle centered at the origin with radius 2.
When you isolate Y^2 and then extarct the squre root you obtain two solutions, call them Y1 and Y2
Y1=SQRT(4-X^2), Y2= -SQRT(4-X^2)
You press[Y=] and type in the right hand side of the equations above, one in Y1= and the other in Y2. Press [GRAPH].

Ih a graphic does not appear within the scree window adjust the window parameters ( [WINDOW]) or Press [ZOOM] and select ZoomIn, ZoomOut, ZoomSTD, etc.

Explore the program Draw accessible by pressing [2nd][DRAW].

Hope it helps

Sep 04, 2009 | Texas Instruments TI-84 Plus Calculator

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