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Texas Instruments TI-89 Calculator - Page 4 Questions & Answers
Error: dependent limit
Dependent limit error may occur if a limit of integration is dependent on the integration variable.For example, integral:int(x^2,x,1,x) is not allowed
9/6/2012 10:51:54 PM •
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Answered
on Sep 06, 2012
Space bar
ALPHA then (-) .
8/27/2012 4:53:08 PM •
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on Aug 27, 2012
My TI-89 Calculator will not turn on.
The damage was battery corrosion. If you CAREFULLY take a damp(not dripping wet) rag and wipe the contacts of the corrosion you may have luck. The batteries just leaked, Very common especially for cheap "Heavy Duty" batteries. Alkalines seem to hold up better in a discharged condition. I hope this helps.Do wash your hands after the cleaning. A q-tip may also be of help. Just wet it and squeeze most of the water from it.
8/10/2012 9:37:12 PM •
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Answered
on Aug 10, 2012
I cant really read some
Hey shrestha,
I've never seen a calculator with display clarity problems.
The only option I could think to offer you is to attempt to adjust the contrast. However, I'm not sure whether or not your TI-89 actually has an option to change the contrast. Because I own a TI-89 Titanium - and although its a wonderful calculator - it does not allow the user to alter the darkness/brightness of the display.
Call Texas Instruments: 1-800-TI- CARES...They are pretty helpful with common questions like this.
Sayonara,
The Math Cheetah
6/7/2012 2:32:24 PM •
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Answered
on Jun 07, 2012
Polar graph half
Check the Theta variable. Give theta a domain wide enough to cover the upper half-plane as well as the lower half-plane. I cannot tell you what limits to use because I do not know the function you are trying to plot.
5/10/2012 12:53:41 AM •
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on May 10, 2012
Change keyboard mapping
Create a program that uses a CUSTOM structure. Assign menus and submenus to built in calculator functions, or to a user defined program/function.For additional details, see Chapter 17 Programming.Here is an example from the manual.:Custom:Title "Vars":Item "L1":Item "M1":Item "Prgm1":Item "Func1":Item "Data1":Item "Text1":Item "Pic1":Item "GDB1":Item "Str1":Title "f(x)":Item "f(x)":Item "g(x)":Item "f(x,y)":Item "g(x,y)":Item "f(x+h)":Item "Define f(x) =":Title "Solve":Item "Solve(":Item " and ":Item "{x,y}":Item "Solve( and ,{x,y})":Title "Units":Item "_m/_s^2":Item "_ft/_s^2":Item "_m":Item "_ft":Item "_l":Item "_gal":Item "_\o\C":Item "_\o\F":Item "_kph":Item "_mph":Title "Symbols":Item "#":Item "\beta\":Item "?":Item "~":Item "&":Title "Internat'l":Item "\e`\":Item "\e'\":Item "\e^\":Item "\a`\":Item "\u`\":Item "\u^\":Item "\o^\":Item "\c,\":Item "\u..\":Title "Tools":Item "ClrHome":Item "NewProb":Item "CustmOff":EndCustm:CustmOnAs to having a user program appear in the catalag, I am not sure you can do that. You may be able to have the program and its variables listed under the VARS and MEMory
4/16/2012 3:27:12 PM •
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on Apr 16, 2012
Can you find stationary points of this equation ((x-1)^1/3)*((x+2)^2/3))
There is only one stationary point for the function
y(x)=((x-1)^(1/3))*((x+2)^(2/3)) and it is pointwith coordinates
x=0 and y=-1.5859At first, first derivation is
y'(x)=x/((x-1)^(2/3))*((x+2)^(1/3)) and we obtained that
y'(0)=0. Then we can find second derivation of the function and for value x=0 we could concluded that
y''(0)>0. In this stationary point it is minimum value of the function.Finally, at the points x=-2 and x=1 we have so called
critical values for this function.See captured images below1. Second derivation for y(x)
2. Graph y(x)
3. Enlarged detail of the graph y(x)
3/28/2012 11:55:21 PM •
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on Mar 28, 2012
My r^2 for regressions isnt being calculated by default
The truth of the matter is that the correlation factor coefficient, and determination coefficients are not defined for all regression models. If they are not defined, they will not be displayed among the statistics. It depends on the model you are trying to fit to your data.
3/27/2012 10:32:11 AM •
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Answered
on Mar 27, 2012
Error:non-algebraic variable in expression
Non-algebraic variable in expression error may occur if a is the name of a PIC, GDB, MAC, FIG, etc., a+1 is invalid. Use a different variable name in the expression or delete the variable
3/22/2012 7:35:18 AM •
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Answered
on Mar 22, 2012
10.3+2(x-4), for =-8
10.3 + 2(x-4), for x=-8
10.3 +2(-8-4)
10.3 +2(-12)
10.3 -24 = -13.7
Answer is -13.7
3/17/2012 11:41:11 PM •
Texas...
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Answered
on Mar 17, 2012
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